Para determinar la distancia en un movimiento rectilíneo uniforme(MRU) recordemos:
[tex]\boxed{\ \boldsymbol{\mathsf{\vphantom{\Big|}d=vt}}}\ }\hspace{30pt} \mathsf{Donde} \hspace{25pt} \begin{array}{l}\mathsf{\blue{\blacktriangleright}\:\:\:v:rapidez}\\\\\mathsf{\blue{\blacktriangleright}\:\:\:d:distancia}\\\\\mathsf{\blue{\blacktriangleright}\:\:\:t:tiempo}\end{array}[/tex]
Extraemos los datos del problema:
[tex]\begin{array}{ccccccccccccc}\mathsf{\boldsymbol{\bigcirc \kern-8pt\triangleright}\ \ \ t=5\ h}&&&&&&&&&&\mathsf{\boldsymbol{\bigcirc \kern-8pt\triangleright}\ \ \ v=5\ km/h}\end{array}[/tex]
Reemplazamos
[tex]\begin{array}{c}\mathsf{d = v\times\: t}\\\\\\\mathsf{d = (300\:\dfrac{km}{h})\times\:(5\:h)}\\\\\\\mathsf{\:d = (300\:\dfrac{km}{\not \!h})\times\:(5\!\not \!h)}\\\\\\\mathsf{\boxed{\boxed{\boldsymbol{\mathsf{d = 1500\:km}}}}}\end{array}[/tex]
Rpta. El tren recorrió 1500 kilómetros.
Tarea similar
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