formula
an = a1 + (n-1) r
an = ultimo termino an = 5
a1 = 1er termino a1 = -5
n = 4+2 = 6 n= numero de treninos
r= razon = ?
(an -a1) / (n-1) = r
(5 -(-5))/(6 -1) = r
(5+5)/5 = r
10/5 = r
2 = r
1er termino = -5
2do termino = -5 +2 = -3
3er termino = -3+2 = -1
4to termino = -1+2 = 1
5to termino = 1+2 = 3
6to termino = 3+2 = 5
queda -5. -3. -1. 1. 3. 5
