tenemos:
x=-2/5 y=3/2 z=4/-3
entonces:
x(y+z)=xy+xz
reemplazando:
-2/5(3/2+4/-3)=-2/5(3/2)-2/5(4/-3)
=>-2/5(3(-3)+2(4)/2(-3)=-6/10+8/15
=>-2/5(-9+8/-6)=-6(15)+10(8)/10(15)
=>-2/5(1/6)=-90+80/150
=>-2/30=-10/150
=>-1/15=-1/15
igualdad verdadera
espero ayude