Respuesta :
[tex] \frac{( \sqrt[5]{ 3^{2}})^{4} .( \sqrt[3]{3})^{6}}{( \sqrt[2]{3^{4})^{6}}} \\ = \frac{(3^{ \frac{2}{5}})^{4}.(3^{ \frac{1}{3} })^{6}}{(3^{\frac{4}{2}})^{6}} \\ = \frac{3^{ \frac{8}{5} }.3^{ \frac{6}{3} }}{3^{ \frac{24}{2}}} \\ =3^{ \frac{8}{5}+2-12 } \\ =3^{- \frac{42}{5} } [/tex]