Respuesta :
Es una suma de cubos:
27(x^3) + 8(c^3)
Ahora factor por factor es asi:
27x^3 = (3x)^3
8c^3 = (2c)^3
[(3x)^3 + (2c)^3] = [3x + 2c] * [(3x)^2 - (3x)*(2c) + (2c)^2]
[3x + 2c] * [9(x^2) - 6xc + 4(c^2)]
27(x^3) + 8(c^3)
Ahora factor por factor es asi:
27x^3 = (3x)^3
8c^3 = (2c)^3
[(3x)^3 + (2c)^3] = [3x + 2c] * [(3x)^2 - (3x)*(2c) + (2c)^2]
[3x + 2c] * [9(x^2) - 6xc + 4(c^2)]
27b^3 +8c^3
3^3b^3 +2^3c^3
(3b +2c) [(3b)^2 - (3b)(2c) +(2c)^2]
(3b + 2c )(9b^2-6bc +4c^2)
3^3b^3 +2^3c^3
(3b +2c) [(3b)^2 - (3b)(2c) +(2c)^2]
(3b + 2c )(9b^2-6bc +4c^2)