Respuesta :
Tenemos dos angulos notables cuyas funciones trigonométricas son conocidas o fáciles de determinar:
37° (angulo agudo menor del triángulo pitagórico 3 4 5)
sen = [tex] \frac{3}{5}[/tex]
cos = [tex] \frac{4}{5}[/tex]
30°
sen = [tex] \frac{1}{2}[/tex]
cos = [tex] \frac{ \sqrt{3}}{2}[/tex]
coc 7° = cos(37° - 30°) = (cos 37°)(cos 30°) + (sen 37°)(sen 30°)
= [tex] (\frac{4}{5})(\frac{ \sqrt{3}}{3}) + (\frac{3}{5})(\frac{1}{2}[/tex]
= [tex] \frac{4\sqrt{3}}{10} + \frac{3}{10}[/tex]
Cos 7° = [tex] \frac{4\sqrt{3} + 3}{10}[/tex]
= [tex] \frac{4(1,73) + 3}{10} = 0,92[/tex]
37° (angulo agudo menor del triángulo pitagórico 3 4 5)
sen = [tex] \frac{3}{5}[/tex]
cos = [tex] \frac{4}{5}[/tex]
30°
sen = [tex] \frac{1}{2}[/tex]
cos = [tex] \frac{ \sqrt{3}}{2}[/tex]
coc 7° = cos(37° - 30°) = (cos 37°)(cos 30°) + (sen 37°)(sen 30°)
= [tex] (\frac{4}{5})(\frac{ \sqrt{3}}{3}) + (\frac{3}{5})(\frac{1}{2}[/tex]
= [tex] \frac{4\sqrt{3}}{10} + \frac{3}{10}[/tex]
Cos 7° = [tex] \frac{4\sqrt{3} + 3}{10}[/tex]
= [tex] \frac{4(1,73) + 3}{10} = 0,92[/tex]