Respuesta :
x=1
f(1)= - 2(1)+1 → f(1)= - 1
g(1)=1² -1 → g(1)=0
h(1)=√(1+3) → h(1) = 2
x=6
f(x)= - 2.6+1→ f(6)= - 12+1 → f(6)= - 11
g(x)=6² -1 →g(x) = 35
h(x)=√(6+3) → h(x) = 3
x=a-3
f(a -3)= - 2(a -3)+1 g(1)=(a-3)² -1 h(1)=√((a-3)+ 3)
f(a -3)= - 2a + 7 g(a -3)=a² - 6a + 8 h(a -3)=√(a)
x=√a
f(√a)= - 2(√a)+1 g(√a)=(√a)² -1 h(√a)=(√(√a)+ 3)
f(√a)= - 2√a+1 g(√a)=a -1 h(√a)=4^√a+ 3
x=0
F(0) = (0+1)/(0-2) G(x)= 2^(-0) - 1- √(-0)
F(0) = -1/2 G(x)= 0
x= - 1
F(x) = (- 1+1)/(- 1-2) G(x)= 2^(-(-1)) - 1- √(-(-1))
F(x) = 0/ - 3 G(x)= 2^1 - 1- √1
F(x) = 0 G(x)= 0
x=-4
F(x) = (-4+1)/(-4-2) G(x)= 2^(-(-4)) - 1- √(-(-4))
F(x) = -3 / - 6 G(x)= 2^4 - 1- √4
F(x) = 1/2 G(x)= 13
X = - a²
F(x) = -a²+1/-a² - 2 G(x)= 2^ a² - 1- √a²
F(x) = a²-1/a² + 2 G(x)= 2^ a² - 1- a
espero que te sirva, salu2!!!!
f(1)= - 2(1)+1 → f(1)= - 1
g(1)=1² -1 → g(1)=0
h(1)=√(1+3) → h(1) = 2
x=6
f(x)= - 2.6+1→ f(6)= - 12+1 → f(6)= - 11
g(x)=6² -1 →g(x) = 35
h(x)=√(6+3) → h(x) = 3
x=a-3
f(a -3)= - 2(a -3)+1 g(1)=(a-3)² -1 h(1)=√((a-3)+ 3)
f(a -3)= - 2a + 7 g(a -3)=a² - 6a + 8 h(a -3)=√(a)
x=√a
f(√a)= - 2(√a)+1 g(√a)=(√a)² -1 h(√a)=(√(√a)+ 3)
f(√a)= - 2√a+1 g(√a)=a -1 h(√a)=4^√a+ 3
x=0
F(0) = (0+1)/(0-2) G(x)= 2^(-0) - 1- √(-0)
F(0) = -1/2 G(x)= 0
x= - 1
F(x) = (- 1+1)/(- 1-2) G(x)= 2^(-(-1)) - 1- √(-(-1))
F(x) = 0/ - 3 G(x)= 2^1 - 1- √1
F(x) = 0 G(x)= 0
x=-4
F(x) = (-4+1)/(-4-2) G(x)= 2^(-(-4)) - 1- √(-(-4))
F(x) = -3 / - 6 G(x)= 2^4 - 1- √4
F(x) = 1/2 G(x)= 13
X = - a²
F(x) = -a²+1/-a² - 2 G(x)= 2^ a² - 1- √a²
F(x) = a²-1/a² + 2 G(x)= 2^ a² - 1- a
espero que te sirva, salu2!!!!