aplicaremos definición
loga B = c si y solo si a^c = B
entonces
log16 X = -3/4 → 16^(-3/4) = x → 1/8 = x
log2 X = - 1/3 → 2^(-1/3) = x → 0.79 = x
log8 X = 5 → 8^5 = x → 32768 = x
xlogx³ = x → logx³ =x/x →10^1 = x³ →³√10 = x → 2.15 = x
log6x= -1 → 6^-1= x → 1/6 = x
log16 x = -3/2 → 16^(-3/2) = x→ 1/64 = x
x = log2 (1/16) → x = -4
espero que te sirva,salu2!!!!