(1/x) + (1/y ) = 4/3; (x + y) / xy = 4/3; 3(x + y) = 4xy; 3x + 3y = 4xy
(1/x) - (1/y ) = 1/3; (y - x) / xy = 1/3; 3(y - x) = xy; 3y - 3x = xy; 3y = xy + 3x; 3y = (y + 3)x;
x = (3y)/(y + 3)
Sustituyendo en la otra ecuación:
3(3y / y + 3) + 3y = 4 (3y / y + 3) y
(9y / y + 3) + 3y = 12y2 / y + 3
9y + 3y (y + 3) = 12y2
9y + 3y2 + 9y = 12y2
18y = 12y2 - 3y2
18y = 9y2
9y2 - 18y = 0
y2 - 2y = 0
y(y - 2) = 0
y = 0
y - 2 = 0; y = 2
x = (3y)/(y + 3); x = 0; x = 6/5
Los números son: 6/5 y 2
