Dada las funciones f (x)= 3x - 2; g (x) = x3. Determine:
a) (f + g)(2)
b) (f - g) (2)
c) (f g) (2)
d) (f / g) (2)
(f + g) (2) = 3x - 2 + x3 = 3(2) - 2 + (2)3 = 6 - 2 + 8 = 12
(f -g) (2) = 3x - 2 - x3 = 3(2) - 2 - (2) 3 = 6 -2 - 8 = -4
(fg) (2) = (3x - 2) . (x3) = 3x4 - 2x3 = 3(2)4 - 2(2)3 = 48 - 16 = 32
(f / g) (2) = (3x - 2) / x3 = (6 - 2) / 8 = 4 / 8 = 1 / 2