Resolvemos :
Sucesión aritmética : (1/3) , (2/3) , 1 , (4/3) , (5/3) ...
Datos : Fórmula : an = a1 + (n-1)*r
a1 = (1/3) an = (1/3) + (n-1)*(1/3)
r = (2/3)-(1/3) = (1/3) an = (1/3)+(n-1)/3
an = ? an = (1+n-1)/3
a6 = ? an = n/3 ----> término n- ésimo.
Ahora hallemos el a6 :
an = n/3
a6 = 6/3
a6 = 2
SaLuDos :)'
