Resuelve aplicando dos veces el metodo de reducción.
22x + 17y =49
31x - 26y =119
Primer Forma:
22x+17y = 49 (1/17) = 22/17x+y = 49/17
31x-26y = 119 (1/26) = 31/26x-y = 119/26
22/17x+y = 49/17
31/26x-y = 119/26
______________
1099/442x = 3297/442
x = 329/442.442/1099
x = 3
*Reemplazamos para hallar el valor de Y
22x+17y = 49 22.3+17y = 49 66+17y = 49 17y = 49-66 17y = -17 y = -17/17 y = -1 Segunda Forma: 22x+17y = 49 (1/22) = x+17/22y = 49/22 31x-26y = 119 (-1/31) = -x+26/31y = -119/31 x+17/22y = 49/22 -x+26/31y = -119/31 _______________ 1099/682y = -1099/682 y = -1099/682.682/1099 Y = -1 * Para Hallar X 22x+17y = 49 22x+17.(-1) = 49 22x = 49+17 22x = 66 x = 3